How Long Does It Take for a Capacitor to Reach 80% Charge in an RC Circuit?

AI Thread Summary
To determine how long it takes for a capacitor to reach 80% charge in an RC circuit, the maximum charge (Q_max) can be calculated using Q = CV, where C is the capacitance and V is the voltage. The charging behavior of the capacitor is described by the equation Q = Q_max[1 - e^(-t/RC)], where R is the resistance and t is the time. To find the time when the capacitor reaches 80% of its maximum charge, the equation can be rearranged to solve for t. The current in the circuit decreases as the capacitor charges, which is a crucial factor in the calculations. Understanding these principles allows for the accurate determination of the charging time in RC circuits.
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Homework Statement



A 4.1e-6 capacitor is connected in series with a 36V battery and a 851 ohlms resistor. At t= 0 the capacitor is uncharged. At what time will the capacitor have 80% of its maximum charge?

Homework Equations


I = V/R
Q = CV
I = Q/t


The Attempt at a Solution


I didn't learn RC circuit much in class since my teacher ran out of time.
But anyway,

So the first thing I did is I found the current which is,

I = .0423 A

Now I'm stuck on this one.

I = Q/t I need to find t, I tried to use .0423 = Q* (.8) / t but the problem is Q is unknown. Any ideas?
 
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You're missing an important fact. The current will constant change as the capacitor charging, approaching zero. Is the 4.1e-6 supposed to be the farad value for it? You can use that in one of the equations you have to find the maximum Q. The equation you are missing is Q = Q_{max}[1 - e^{(-t/RC)}], I believe. Try getting the [1 - e^{(-t/RC)}] to get to the amount of the maximum charge you need.
 
MrNerd said:
You're missing an important fact. The current will constant change as the capacitor charging, approaching zero. Is the 4.1e-6 supposed to be the farad value for it? You can use that in one of the equations you have to find the maximum Q. The equation you are missing is Q = Q_{max}[1 - e^{(-t/RC)}], I believe. Try getting the [1 - e^{(-t/RC)}] to get to the amount of the maximum charge you need.
Thanks for your reply
But how do I find out out the max Q if q and t is unknown?
 
Last edited:
I think you misunderstood what I meant by max Q. The maximum Q is the highest charge the capacitor can hold with a given voltage. t is just the time, right? So you simply need to solve for t. I don't know if you already did this, but the inverse function of e is a natural log, shown as ln. So the natural log of e^x would give you x, and e^(lnx) would give you x as well. Remember, you want 80% of the maximum charge. The left q(the one by itself and equaling the other things) is the one you want at time t.
 
Solve for t as a function of R and C.
 
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