How long does it take for a plane to come to a stop in an emergency landing?

AI Thread Summary
A light plane weighing 2,500 lb makes an emergency landing at 120 ft/s on a short runway, using a cable to drag a 250 lb sandbag. The friction force is calculated using the coefficient of friction (0.4), resulting in a total friction force of 3,200 lb. An additional retarding force of 300 lb from the plane's brakes is also considered. The combined forces lead to a differential equation that, when solved, indicates the plane takes 23 seconds to come to a complete stop. There is a concern regarding the units used for the retarding force in the calculations.
tylerc1991
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Homework Statement



This is a problem from K & K, but I changed it very slightly.

A light plane weighing 2,500 lb makes an emergency landing on a short runway. With its engine off, it lands on the runway at 120 ft/s. A hook on the plane snags a cable attached to a 250 lb sandbag and drags the sandbag along. If the coefficient of friction between the sandbag and the runway is 0.4, and if the plane's brakes give an additional retarding force of 300 lb, how long does it take for the plane to come to a stop?

Homework Equations



f = force of friction = mu * m * g

viscous force = -C * v, where C is some constant

F = ma

The Attempt at a Solution



Let's say that the positive x is positive direction. The acceleration of the sandbag and the plane is the same since they are connected by a cable. The force of friction is given by

f = mu * m_sandbag * g = - 3200 lb*ft/s^2

And the additional retarding force from the brakes is

f_v = - 300 v(t) lb*ft/s

So we have

- 3200 - 300 v(t) = m_total * a

or

-3200 - 300 v(t) = 2750 * dv/dt.

After I solved this differential equation and set v(t) = 0, I found that the time required for the plane to come to a stop is t = 23 seconds.

Does this look right? Thank you!
 
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I think f_v has the wrong units.
 
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