How Long to Double Your Money with Compound Interest?

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Homework Help Overview

The discussion revolves around determining the time required for a fixed deposit investment of $30,000 to double at an interest rate of 4.3% per annum, compounded annually. Participants are exploring the concept of compound interest and its application in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the appropriate method to find the solution and discussing relevant equations related to compound interest. Some are attempting to derive a general equation based on specific cases of compounding.

Discussion Status

The discussion is ongoing, with participants sharing their understanding of compound interest and attempting to clarify the method needed to solve the problem. Some guidance has been offered regarding the formula for compound interest, but there is no explicit consensus on the approach yet.

Contextual Notes

There is a mention of potential confusion regarding the assignment of this problem, particularly for those who may not have covered compound interest in their coursework. This raises questions about the assumptions and background knowledge expected for solving the problem.

jahaddow
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A fixed deposit investment attracts interest of 4.3% p.a. compounded annually. How long will $30 000 take to double in value?
 
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jahaddow said:
A fixed deposit investment attracts interest of 4.3% p.a. compounded annually. How long will $30 000 take to double in value?

What have you tried? What are the relevant equations?
 
This is all I know, I don't know what method should be used to find the answer?
 
That's very peculiar! If you aren't taking a course that has discussed "compound interest", why have you been assigned a problem like this? If you are then surely there are formulas for compound interest in your textbook aren't there?

If I remember correctly, after n years, an amount S at r rate of interest (so that 100r% is the annual percentage rate) compounded annually is given by [itex]S(1+ r)^n[/itex]. Set that equal to 2S, cancel the "S"s and solve for n.
 
A powerful strategy is to think about the specific case and try to obtain a general equation.

The first year, you have $30 000

The second year it is compounded by $30 000 x .043 so you have 30 000 + 30 000 x .043
= 30 000 (1.043)

The next year your money increases again by 30 000 (1.043) (.043) for a total of 30 000 (1.043) + 30 000 (1.043) (.043) = 30 000 (1.043) (1.043) = 30 000 (1.043)^2

By now you should have noticed a pattern.
 

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