How long until the ball hits the ground?

  • Thread starter Thread starter hyde2042
  • Start date Start date
  • Tags Tags
    Ball Ground
AI Thread Summary
A ball is thrown downward from a height of 30 meters at an initial velocity of 8 m/s, and the goal is to determine the time until it hits the ground, considering negligible air resistance and a gravitational acceleration of 9.8 m/s². The initial calculation using the equation deltaX = Vi + (1/2)a(t²) resulted in 2.12 seconds, but the correct answer is 1.79 seconds. The confusion arises from the quadratic equation formed during the calculations, leading to a misunderstanding of the variables involved. The discussion emphasizes the importance of correctly applying the kinematic equations and solving quadratic equations to find the accurate time of impact. Clarification on the quadratic formula is requested to resolve the confusion surrounding the calculations.
hyde2042
Messages
26
Reaction score
0

Homework Statement



A ball is thrown downward from a height of 30m at 8m/s. How long until it hits the ground?
(Air resistance is negligible and gravity is 9.8m/s


Homework Equations


I tried deltaX=Vi+(1/2)a(t^2) and came out with 2.12, but the solution says it's 1.79.


The Attempt at a Solution



30=8+(1/2)(9.8)(t^2)
22=4.9(t^2)
sqrt4.49=sqrt(t^2)
t=2.12
 
Physics news on Phys.org
Are you not missing a t?
V = V_i + a t
so
\Delta x = V_i \mathbb{t} + \frac12 a t^2
 
Thank you, but I'm afraid I'm evenb more confused by the additional t.

I ended up at 30-8t=4.9(t^2)

What I keep doing after that seems to make it more complicated than it should be. COuld you possibly point me in the right direction? Thank you for your time.
 
It's a standard quadratic equation, of the form ax2 + bx + c = 0.
How do you solve one of those?
 
Ah... hate when I over look simple things. Thank you very much.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top