How Long Until the Police Car Overtakes the Speeder?

AI Thread Summary
To determine how long it takes for the police car to overtake the speeder, two equations of motion need to be set up: one for the speeder moving at a constant speed of 34 m/s and another for the police car accelerating from rest at 2.2 m/s². The position equations for both vehicles should be established, with the origin set at the point where the speeder passes the police car. By equating the two position equations, the time variable can be solved. Clarification on the setup and solving process is essential for understanding how to approach the problem effectively.
delfam
Messages
34
Reaction score
0

Homework Statement


speeder passes a police car at 34 m/s. Police car from rest accelerates with a uniform acceleration of 2.2 m/s^2. How much time till the police car overtakes the speeder?


Homework Equations


V=Vi + at
X=Xi +Vit + 1/2at^2
a= 2.2m/s^2 V=34m/s Vi=0

The Attempt at a Solution


not sure what equation to use, I think the second one just because it's a question passed on position. Vi=0 so the equation then would be t^2 = 2(X-Xi)/a, but where do I get X and Xi from?
 
Physics news on Phys.org
Hello!
You have two bodies - police car and speeder car. So it's good idea to use two X's, one for police car position Xp and other for speeder Xs, best choice for origin would seem to be at the point where speeder passes police car. So write equation for Xp and Xs with values given in problem statement and solve for t.
 
bump, I still have no clue how to even start this question. Do I need to set up two equations, one for the car and one for the cop, then set them equal, I'm just confused.
 
yes ;]
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top