How many electrons would transfer 1 J of energy to a screen?

AI Thread Summary
The discussion focuses on calculating the kinetic energy of an electron and determining how many electrons are needed to transfer 1 joule of energy to a screen. The kinetic energy of an electron moving at 5.0 * 10^5 m/s is calculated to be 1.14 * 10^-19 J. The initial calculation for the number of electrons needed to transfer 1 J was incorrectly stated as 1.14 * 10^19, while the correct answer is 8.8 * 10^18. The error was attributed to misunderstanding the relationship between the exponent and the mantissa in the calculations. The participant acknowledges the mistake and expresses gratitude for the clarification.
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An elecetron has a mass of 9.11 * 10^-31 kg. If it moves across a television picture tube at a speed of 5.0 * 10^5 m/s. Calculate:
a) it's kinetic energy
b)how many such electrons would transfer 1 J of energy to the screen.

My answer to a) is 1.14 * 10^-19 J, which is correct.
My answer to b) is 1.14 * 10^19, which is not correct. The correct answer is 8.8 * 10^18. How did they get that? because if 1 electron has 1.14 * 10^-19 J then won't we need 1.14 * 10^19 electrons for 1 J ?
 
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sakonpure6 said:
My answer to a) is 1.14 * 10^-19 J, which is correct.
My answer to b) is 1.14 * 10^19, which is not correct. The correct answer is 8.8 * 10^18. How did they get that? because if 1 electron has 1.14 * 10^-19 J then won't we need 1.14 * 10^19 electrons for 1 J ?

Changing the sign of the exponent is not the same as division... What about the mantissa of the number?
 
om >.< I know what i did wrong! Stupid mistake. Thanks for that comment.
 
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