How many grams of cold water necessary to lower temperature in container

AI Thread Summary
To determine how many grams of 20°C water are needed to lower the temperature of 100 grams of 80°C water to 50°C, the equation q = c * m * deltaT is essential. The heat lost by the 80°C water (q) is equal to the heat gained by the 20°C water, with the latter being the negative of the former. This relationship arises because the heat energy lost by the hotter water is transferred to the cooler water. By applying these principles, one can solve for the required mass of the cooler water. Understanding these concepts is crucial for solving the problem effectively.
Paulo Serrano
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Homework Statement


How many grams of 20 degree C water do I need to add to 100 grams of 80 degree C of water to get the final temperature down to 50 degrees C?


Homework Equations


I'm sure it's a pretty simple equation, but I don't know it. (I'm studying a lot of different things at once and am not in school)


The Attempt at a Solution


Not sure.

Thanks :)
 
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First you need to know the equation for energy, which is q=c*m*deltaT, where deltaT is T(final)-T(initial). You also know that q of the 20 degree water equals the negative of the 80 degree water. Given this, you should be able to solve for grams of 20 degree water.
 
q is heat energy, correct? Why is one the negative of the other?
 
One is negative of the other because the heat that leaves the 80 degree water is added to the 20 degree water.
 
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