How many grams of water at 20 degrees Celsius can be converted into steam

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To determine how many grams of water at 20 degrees Celsius can be converted into steam at 500 degrees Celsius using 10 kJ of energy, the process involves three steps: heating the water to 100 degrees Celsius, converting it to steam, and then heating the steam. Each step's heat requirement can be expressed in terms of mass, leading to a single equation that sums the energy for all three steps equal to 10 kJ. The calculations involve using specific heat values for water and steam to find the mass, resulting in a solution of approximately 2.94 grams. The discussion emphasizes the importance of correctly setting up the equations and understanding how to express heat in terms of mass. Ultimately, the conclusion reached is that 2.94 grams is the correct answer for the conversion.
DB
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can someone give me a hand on this one?

How many grams of water at 20 degrees Celsius can be converted into steam at 500 degrees Celsius with 10 kJ of energy?

wat i know is that this question is 2 parts: Water being heated to 100 C (80 C change)using the specific heat of water n then having a temperature change of 400 C using the specific heat of steam.

wat i don't understand is how i am supposed to split up the 10 kJ? do i have to have only 1 equation?

thanks in advance
 
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sorry guys, i just realized there was a chemistry section, my bad...
 
There are three steps: (1) Heating the water, (2) converting water to steam, (3) Heating the steam.

Express the heat required for each step in terms of the mass, m. Set the total energy equal to 10 kJ. That's the equation you want.
 
okay but should i have 3 equations or 1?
 
You'll end up with a single equation. (Reread my previous post.)
 
i don't no wat u mean when u say express the heat in terms of mass
 
wat i tried was adding each step and then dividing 10000J by the sum to solve for m, i got 2.94 grams...?
 
DB said:
i don't no wat u mean when u say express the heat in terms of mass
For example: For step 1, how much heat is required to heat "m" grams of water from 20 degrees to 100 degrees?
 
okay so now I've got 3 values for "m":

m=\frac{E}{80*4.19}

m=\frac{E}{2262}

m=\frac{E}{400*2.01}

now I am stuck :(
 
  • #10
There is only one "m". What you should have is three values for E: E_1, E_2, E_3. Your equation would be: E_1 + E_2 + E_3 = 10 kJ; solve for m.
 
  • #11
ya that's wat i did when i said i got 2.94 grams
 
  • #12
anyway I am convinced that the answer is 2.94 grams, thanks for the tips doc al, i apreciate it
 
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