How many nodes of each degree are there in this graph?

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Homework Help Overview

The discussion revolves around determining the number of nodes of each degree in a graph, specifically focusing on the degrees of 2 and 5 among a total of 6 vertices. Participants reference the handshake theorem and the implications of vertex degree parity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the number of vertices and their degrees, using the handshake theorem to formulate equations. There is a discussion about the validity of proposed distributions of vertex degrees and whether they satisfy the theorem's conditions.

Discussion Status

Several participants have offered interpretations of the problem and proposed potential distributions of vertex degrees. There is a sense of agreement on the approach, but no explicit consensus on the final solution has been reached.

Contextual Notes

Participants are working under the constraints of the handshake theorem and the requirement for an even number of vertices of odd degree. The exact formulation of the equations and the assumptions about the graph's structure are still being discussed.

r0bHadz
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Homework Statement
A graph has 12 edges and 6 nodes, each of which has degree of 2 or 5. How many nodes
are there of each degree?
Relevant Equations
handshake theorem.
2m = summation of degree of each vertice where m = # of edges
there must be an even number of vertices of odd degree, and from the handshake theorem, 2m = 2(12) = 24

the only way we can get this from 6 vertices using 2 and 5 is:

4 vertices of degree 5, 2 vertices of degree 2

does this seem correct??
 
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If we denote with ##x## the number of nodes with degree ##2## and with ##6 - x## the number of nodes with degree ##5## then according to the theorem you say, you have a simple equation of the first degree in ##x##.
Its solution gives what is asked.
 
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QuantumQuest said:
If we denote with ##x## the number of nodes with degree ##2## and with ##6 - x## the number of nodes with degree ##5## then according to the theorem you say, you have a simple equation of the first degree in ##x##.
Its solution gives what is asked.
So do I just plug and chug to find out? It seems like 4 of degree 5 and 2 of degree 2 meets the requirements?
 
r0bHadz said:
So do I just plug and chug to find out? It seems like 4 of degree 5 and 2 of degree 2 meets the requirements?

I would say yes, it seems so, but you must first form the equation and then solve it, in order to see it.
 

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