- #1

nubey1

- 5

- 0

## Homework Statement

The length of a string attached to a pendulum is measured with a precision of (+or-)0.2. The time of the oscillation is measured to a precision of (+or-)0.1. How many periods must you measure so that the contribution of the uncertainty in time is smaller than the uncertainty in length, when calculating g?

## Homework Equations

T=2pi(l/g)^(1/2)

## The Attempt at a Solution

g=((2pi)^2(l+delta:l))/(T+delta:T)^2

I don't know where to go from here.

Delta l and T are the error in those measurements.