How Many Radioactive Atoms Are in a 6GBq Sample of 99mTc and What Is Its Mass

AI Thread Summary
To determine the number of radioactive atoms in a 6GBq sample of 99mTc, the decay constant (λ) is calculated using the half-life of 6 hours, resulting in λ = 0.115. This leads to an estimated number of nuclei (N) of approximately 5.21 × 10^17. The mass of the sample is then calculated using the formula mass = (no. nuclei * mass number) / Avogadro's number, yielding a mass of about 8.18 × 10^-7 kg. The discussion highlights the importance of the half-life in calculating both the number of atoms and the mass of the radioactive sample. Overall, the calculations demonstrate the relationship between radioactivity, decay constants, and mass in radioactive materials.
Millano
Messages
6
Reaction score
0

Homework Statement



How many radioactive atoms are present in a sample of 6GBq of 99mTc and what is the approximate mass of the sample?

Homework Equations



A= λN
half life = ln2/λ
mass = (no.nuclei * mass number)/avorgado number
avogado = 6.023×10^23
half life = 6 hours

The Attempt at a Solution



worked out λ using the above half life (6 hours) and then N (no. nuclei). My problem is that we was not given the half life to beign with. Is there any other way of working it out without the half life ?
 
Physics news on Phys.org
N = 6GBq / λ λ= ln2 / half life λ = 0.693 / 6 λ = 0.115N = 6 GBq / 0.115N = 5.21 × 10^17mass = (no. nuclei * mass number) / avogado number mass = (5.21 × 10^17 * 99) / 6.023×10^23mass = 8.18 × 10^-7 kg
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
4
Views
2K
Replies
8
Views
3K
Replies
6
Views
5K
Replies
5
Views
2K
Replies
16
Views
3K
Replies
7
Views
1K
Replies
2
Views
2K
Replies
7
Views
3K
Back
Top