How many real roots does the equation (9x^5)-(4x^4)+(8x^3)-4x+1=0 have?

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Homework Statement



Show that the equation (9x^5)-(4x^4)+(8x^3)-4x+1=0 has exactly 3 real roots.

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The Attempt at a Solution


I found a derivative of (45x^4)-(16x^3)+(24x^2)-4. I am not sure how to set this equal to zero
 
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Use the intermediate value theorem, if f(x) is a continuous function and there exist point a<b such that f(a)<0<f(b) or f(a)>0>f(b) then there is a point c, where f(c)=0.

My advice is to plot the graph and find approximatly where they are and then use the above to prove it so.
 
Also, you should show there's only one inflection point, so you have only 3 roots and not 5.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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