How Much Ballast to Achieve Upward Acceleration?

  • Thread starter Thread starter WhoCares357
  • Start date Start date
  • Tags Tags
    Acceleration Mass
AI Thread Summary
To achieve an upward acceleration of 1.3 m/s² for a 305 kg research balloon currently descending at 1.4 m/s², the net force acting on the balloon must be calculated. The initial downward force due to gravity is greater than the lift, resulting in a negative acceleration. To switch to upward acceleration, a specific amount of ballast must be removed to adjust the mass and change the net force. The discussion raises questions about the balloon's current acceleration and the necessary calculations to determine the correct amount of ballast needed. Understanding the forces and accelerations involved is crucial for solving the problem effectively.
WhoCares357
Messages
1
Reaction score
0

Homework Statement


A research balloon of total mass 305 kg is descending vertically with a downward acceleration of 1.4 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 1.3 m/s2, presuming that the upward lift of the balloon does not change.


Homework Equations


$$F=ma$$


The Attempt at a Solution


I'm having trouble because the original acceleration is positive and the final one is positive. How do I set up the proportion with what I have? Setting $$-305*1.4=m_2*1.3$$ doesn't work.
 
Physics news on Phys.org
What is the acceleration of the freely falling balloon?
why the balloon's acceleration is reduced?
What is the net acceleration of the balloon when it is moving up?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top