How Much CO Remains at Equilibrium in a 3L Flask?

AI Thread Summary
The discussion revolves around calculating the mass of carbon monoxide (CO) at equilibrium in a reaction involving hydrogen (H2) and carbon dioxide (CO2) in a 3L flask. The user initially calculated 55g of CO using ICE tables and the equilibrium constant, while the worksheet indicated 13.0g. Other participants confirmed the user's calculation, suggesting that the worksheet's answer is likely incorrect given the equilibrium constant of 3.59. The consensus is that the user’s approach and answer are valid, leading to the conclusion that the worksheet may contain an error. The discussion highlights the importance of verifying calculations in chemistry problems.
Coco12
Messages
272
Reaction score
0

Homework Statement



H2+CO2=CO+H2O
if 1.50 mol of each chemical species are placed in a 3.00l flask and allowed to achieve the equilibrium above, what mass of Co will be present at equilibrium?

Homework Equations



Keq= concentration of products each raised to the number of moles in equation/ concentration of reactants raised to the number of mols

The Attempt at a Solution


I used the ice tables and substituted the variables then used the equilibrium constant equation to determine x

My answer came out to be 55 g but the answer on the worksheet said 13.0 g. I think the answer on the worksheet is wrong, because I double checked my answer and still didn't get it? Just wondering for a 2nd opinion from someone
 
Physics news on Phys.org
Sigh. What is the value of the constant?
 
Borek said:
Sigh. What is the value of the constant?

The value of the constant is 3.59
 
Coco12 said:
The value of the constant is 3.59
Your answer seems right. With that equilibrium constant, you would expect to end up with more than 1.5 moles of CO, rather than less.

Chet
 
Chestermiller said:
Your answer seems right. With that equilibrium constant, you would expect to end up with more than 1.5 moles of CO, rather than less.

Chet

Ok thanks, I think the answer on the sheet is wrong
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top