How Much Does Neutron Star Material Weigh on Earth?

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To determine the weight of 1.1 cubic centimeters of neutron star material on Earth, the density of the neutron star must first be calculated using its mass and volume. The mass of the neutron star is 1.99e+30 kg, and its radius is 9 km, leading to a calculated density of approximately 6.5168e17 kg/m³. After converting the volume of the material from cubic centimeters to cubic meters, the weight is found by multiplying the volume by the density and Earth's gravity, resulting in 7.0323e16 N. The user expressed frustration with their answer not being accepted, prompting suggestions to double-check the conversion calculations. Accurate conversions and calculations are crucial for solving physics problems correctly.
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Basic mass to weigh conversion?

Consider a neutron star of mass M = 1.99e+030 kg and a radius of R = 9 km.
Assuming uniform density, how much would 1.1 cubic centimeters of neutron star material weigh on the surface of the earth?

Homework Equations


Volume of Sphere = (4/3)pi(r^3)
density = Mass/Volume
gravity = 9.81 m/s^2

First I converted 9km to 9000m, and 1.1cm^3 to .011m^3
solve for density; (M=1.99e30)/(vol=(4/3)pi(9000^3) = 6.5168e17

(.011 x 6.5168e17) x 9.81 = 7.0323e16 N

its not accepting my answer
 
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danimal8f said:
Consider a neutron star of mass M = 1.99e+030 kg and a radius of R = 9 km.
Assuming uniform density, how much would 1.1 cubic centimeters of neutron star material weigh on the surface of the earth?

Homework Equations


Volume of Sphere = (4/3)pi(r^3)
density = Mass/Volume
gravity = 9.81 m/s^2

First I converted 9km to 9000m, and 1.1cm^3 to .011m^3
solve for density; (M=1.99e30)/(vol=(4/3)pi(9000^3) = 6.5168e17

(.011 x 6.5168e17) x 9.81 = 7.0323e16 N

its not accepting my answer


Welcome to PF.

Maybe you want to check that conversion?
 


why thank you... I'm an idiot
 
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