MHB How Much Does the Bag Cost in This Math Problem?

  • Thread starter Thread starter Johnx1
  • Start date Start date
Johnx1
Messages
48
Reaction score
0
I'm sure I'm correct, but i want to make sure.

A watch costs twice as much as a bag that costs \$w. the total cost of the two items is \$177.

a) how much does the bag cost?

my answer: 2w + w = 177

3w = 177

w = 59

so the bag cost \$59b) How much does the watch cost?

2w. so 2*59 = \$118
 
Mathematics news on Phys.org
Johnx said:
I'm sure I'm correct, but i want to make sure.

A watch costs twice as much as a bag that costs \$w. the total cost of the two items is \$177.

a) how much does the bag cost?

my answer: 2w + w = 177

3w = 177

w = 59

so the bag cost \$59

Very good. This is the correct answer.

b) How much does the watch cost?

2w. so 2*59 = \$118

Again, this is the correct answer. Keep up the good work!
 
Chris L T521 said:
Very good. This is the correct answer.
Again, this is the correct answer. Keep up the good work!

Chris, thank you for the time and checking my answers.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top