How Much Energy Does It Take to Move a Charge to the Apex of a Charged Cone?

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The discussion revolves around calculating the energy required to move a test charge to the apex of a uniformly charged insulating cone. Participants explore different methods to determine the potential energy, considering the charge distribution and geometry of the cone. There is a consensus that the charge density can be treated as uniform, and the angle of the cone does not affect the potential at the apex. Concerns about insufficient data, such as the cone's radius, are addressed by suggesting the introduction of additional variables that may simplify the problem. The conversation emphasizes the importance of understanding the geometry and charge distribution to solve the energy calculation effectively.
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Homework Statement


A cone made of an insulating material has a total charge Q spread uniformly over its sloping surface. Calculate the energy required to bring a small test charge q from infinity to the apex A of the cone. The cone has a slope of length L.

Homework Equations



The Attempt at a Solution


Since work done equals change in P.E so I have to find the P.E of the system.
Suppose at a distance x from A I take an elementary cylinder of length dx. Let charge density be σ.
dQ=σdV

Wait! I don't know PE of disc and this seems an extremely time consuming process to me. Is there any other method?
 
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The charge is present at the surface of the cone only. For the apex, there is a nice way to parametrize the surface and its distance to the apex.
 
utkarshakash said:

Homework Statement


A cone made of an insulating material has a total charge Q spread uniformly over its sloping surface. Calculate the energy required to bring a small test charge q from infinity to the apex A of the cone. The cone has a slope of length L.

Don't we also need to know the largest diameter?
 
rude man said:
Don't we also need to know the largest diameter?
No. Consider a circular element at distance r from the apex. If you vary the angle of the cone, that element moves around but stays the same distance r from the apex and carries the same fraction of the total area, hence the same charge. Thus the potential it generates at the apex is independent of the cone angle.
 
mfb said:
The charge is present at the surface of the cone only. For the apex, there is a nice way to parametrize the surface and its distance to the apex.

Can you tell me what is it?
 
Use anything (linear) you like, it will probably work.
 
mfb said:
Use anything (linear) you like, it will probably work.

Ok so I take an elementary ring at a distance x from the apex along the surface of cone. Is it alright?
 
Just go on and test it?
 
mfb said:
Just go on and test it?

But nothing other than slope length L is given. I'm falling short of data. Even the radius is not given.
 
  • #10
Just introduce additional variables, if you like. If they drop out later (they should do this here), everything is fine again.
 
  • #11
utkarshakash said:
But nothing other than slope length L is given. I'm falling short of data. Even the radius is not given.

What is the expression for differential area (dA) ?
 
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