How Much Energy is Extracted from Uranium-235 Through Nuclear Fission?

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Homework Statement



What proportion of the total energy in Uranium-235 is extracted through nuclear fission?

In 2001, the world electricity consumption was 13.81 trillion kWh. Assuming 50% efficiency in converting and distributing the power, and imagining that all production was nuclear, how many kg of radioactive waste (Xe and Sr) would have been created?

Homework Equations



1 n + 235U -> 140Xe + 94Sr + 2 n + gamma

1 MeV = 1.602x10^-13 J
1 kWh = 3.6x10^6 J

The Attempt at a Solution



Using the reaction and the binding energies the released energy is equal to 175 MeV.

how do i calculate the proportion of the extracted and total energy?

how do i use the % of efficiency and the global production to calculate the waste?
Please help.
 
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i forgot that the total energy of Uranium is the binding energy i think that is 1786 MeV.
 
i don't know how to relate the total and the released energy, and how to relate the 50% efficiency with the released energy and the global consumption... please help :(?
 

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