How Much Energy is Required to Double the Kinetic Energy of Iron Atoms in a Rod?

AI Thread Summary
To double the average kinetic energy of iron atoms in a 500g rod at 25 degrees Celsius, the required thermal energy must be calculated using the equation EH = mcΔT. The initial calculation yielded 56.5 J, which is significantly lower than the expected answer of 6.73 x 10^4 J. The discussion highlights the need to convert grams to kilograms and determine the final temperature necessary to achieve the desired kinetic energy increase. Participants emphasize the importance of showing complete work for clarity in problem-solving. Understanding the relationship between temperature change and kinetic energy is crucial for accurate calculations.
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Thermal energy question??

Homework Statement


a 500g iron rod has a temp. of 25 degrees C. how much thermal energy must be added to the rod to double the average kinetic energy of the iron atoms?


Homework Equations


EH = mc\DeltaT


The Attempt at a Solution


EH = (0.005 kg)(452 J/kg x \circC)
= 56.5 J
but the answer should be 6.73 x 104
help?
 
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roxxyroxx said:

Homework Statement


a 500g iron rod has a temp. of 25 degrees C. how much thermal energy must be added to the rod to double the average kinetic energy of the iron atoms?


Homework Equations


EH = mc\DeltaT


The Attempt at a Solution


EH = (0.005 kg)(452 J/kg x \circC)
= 56.5 J
but the answer should be 6.73 x 104
help?
You have to show your work completely. '

First of all, how many kg does 500 grams represent?

What temperature does the iron have to reach in order to double its kinetic energy?

AM
 
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