How Much Fluid Was Injected Into the Capillary?

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The discussion focuses on calculating the volume of fluid injected into a capillary with a diameter of 76 micrometers using pressure and Poiseuille's Law. The user calculated the pressure based on fluid density and height difference, resulting in 521.7 Pa. However, their computed volume of 37.676 m^3 seems implausible for such a small capillary. The user realizes they overlooked an important detail in their calculations, leading to an exaggerated result. This highlights the importance of careful attention to detail in fluid dynamics calculations.
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Homework Statement



So for an experiment, we injected a small volume of fluid into a capillary (76 micrometer diameter) through a pressure difference and I'm trying to calculate exactly how much was injected.

diameter of capillary = 76e-6 m
height one end was raised above the other = 5.334 cm = 0.05334 m
density of the fluid = .997 g/mL
viscosity of the fluid = 1 g/(m*s) = 0.001 kg/(m*s)
elapsed time during injection = 31 s
capillary length = 78 cm = 0.78 m

Homework Equations



The formulas we are given are:
pressure = (density) * (gravitational constant) * (change in height)
volume injected = (pressure * pi * d^4 * t)/(128 * viscosity * capillary length) <-- Poiseuille's Law

The Attempt at a Solution



Based on my calculations, I'm getting:

P = (997 kg/m^3)*(9.81 m/s^2)*(0.05334 m) = 521.7 Pa
V = (521.7 Pa)(pi)(76e-6 m)(31s)/(128 * .001 kg/(m*s) * .780 m) = 37.676 m^3

Clearly, we didn't inject anywhere close to that much into a tiny capillary, so where am I going wrong?

Thanks in advance!
 
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nayanm said:
diameter of capillary = 76e-6 m
volume injected = (pressure * pi * d^4 * t)/(128 * viscosity * capillary length) <-- Poiseuille's Law
V = (521.7 Pa)(pi)(76e-6 m)(31s)/(128 * .001 kg/(m*s) * .780 m) = 37.676 m^3
Is there something you forgot?
 
haruspex said:
Is there something you forgot?

Yes. My dignity.

Thank you so much. I can't believe I didn't catch that.
 
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