How Much Force Is Exerted on the Floor When Pushing a Box?

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When pushing a 25 kg box across a wooden floor at constant speed, the force exerted on the floor can be calculated using the coefficient of kinetic friction (μk = 0.20). The frictional force (Ff) is determined by multiplying the coefficient of friction by the normal force, which is equal to the weight of the box (mass x gravity). In this case, the frictional force is 5 N, indicating the force exerted on the floor. The discussion highlights confusion regarding the distinction between the force on the box and the force on the floor. Understanding these forces is crucial for solving related physics problems.
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Homework Statement


you push a 25 kg box across a wooden floor at constant speed. how much force do you exert on the floor? (mu(k) = 0.20

Homework Equations



Ff=<uFn

The Attempt at a Solution


this is wat i get so far
mass = 25kg
uk= .20

.20<.20x25
.20<5

is this correct? I am confuse coz of how much force you exert on the floor not on the box?
i need help guys
 
Last edited:
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solve your other question
you'll get this one too
 
hav0c said:
solve your other question
you'll get this one too

what do you mean?
 
What forces does the box exert on the floor?
 
jamesblim168 said:
what do you mean?
your thread "How to calculate force applied?" contains the answer
 
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