How Much Force is Needed to Move a Wire with Soapy Solution?

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Homework Help Overview

The problem involves calculating the force required to move a wire submerged in a soapy solution, with specific parameters including surface tension and wire length. The context is rooted in fluid mechanics and surface tension concepts.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between surface tension and force, with one individual attempting to apply the formula γ = F/l. Questions arise regarding unit conversions and whether additional equations are necessary for the solution.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the figure referenced in the problem. Some guidance has been offered regarding visualizing the setup, but no consensus or resolution has been reached yet.

Contextual Notes

Participants express uncertainty about the visualization of the problem setup, which may be affecting their understanding and approach to the calculations. There is a repeated emphasis on the need to carefully consider the figure provided.

EmilyO89
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1.
Calculate the force needed to move the wire in the figure (Figure 1) if it holds a soapy solution (surface tension is 0.025 N/m) and the wire is 16.0 cm long.

Express your answer to two significant figures and include the appropriate units.

giancoli_cp7.ch10.p67.jpg
2.

γ(surface tension) = F (force) / l (length)

3. My attempt at a solution

γ=F/l so γl=F

γ: 0.025 N/m

l: 16cm or 0.16m

0.025 N/m * 0.16m = 0.004 N or 4.0 * 10-3N

I know this must be ridiculously easy but I really can't figure out what I'm missing here. Do I need another equation to solve this problem? Am I messing up the units somehow?
 
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EmilyO89 said:
1.
Calculate the force needed to move the wire in the figure (Figure 1) if it holds a soapy solution (surface tension is 0.025 N/m) and the wire is 16.0 cm long.

Express your answer to two significant figures and include the appropriate units.

giancoli_cp7.ch10.p67.jpg
2.

γ(surface tension) = F (force) / l (length)

3. My attempt at a solution

γ=F/l so γl=F

γ: 0.025 N/m

l: 16cm or 0.16m

0.025 N/m * 0.16m = 0.004 N or 4.0 * 10-3N

I know this must be ridiculously easy but I really can't figure out what I'm missing here. Do I need another equation to solve this problem? Am I messing up the units somehow?
I can't help at this time, but someone will pretty soon:) I just have time to say welcome to PF and hope you stay around and get to know some people:D
 
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Look very carefully at the second part of the figure.

Chet
 
Chestermiller said:
Look very carefully at the second part of the figure.

Chet

Got it. Thank you!

I knew it must be something simple like that but I was getting hung up because I just could not visualize exactly what this thing is supposed to look like.
 

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