How Much Force Is Needed to Move an Object Up an Inclined Plane?

AI Thread Summary
To move a 16 kg object up a frictionless inclined plane at a 60-degree angle with a uniform acceleration of 2.0 m/s², the necessary force must overcome both the gravitational component acting down the plane and provide the required acceleration. The gravitational force acting parallel to the incline is calculated using mg*sin(θ), where m is the mass and θ is the angle of the incline. The total force required is the sum of this gravitational force and the force needed for acceleration, expressed as F = mg*sin(θ) + ma. It is essential to ensure that calculations consider the correct angle and gravitational force. The solution requires careful verification to ensure accuracy.
nutzweb
Messages
12
Reaction score
0
hey guys! i need some help, a big help. this is urgent... can somebodyhelp me solve this problem:

what force, applied parallel to the plane, is necessary to move a 16 kg object up africtionless palne with a uniform acceleration of 2.0 m/s2 if the plane makes an angle of 60 degrees with the horizontal?

pls somebody help me. i really need it badly. hope somebody would reply today. thanks...
 
Physics news on Phys.org
Is the plane on the surface of earth, so that the body is subject to a gravitational force of (16 kg)*(9.8 m/s^2)?

Is the acceleration wrt the plane or the ground? Makes a big difference.

I assume the answers are yes and wrt the plane.

The NET force necessary to move the body 2 m/s^2 is simply mass * acceleration = (16 kg)*(2 m/s^2).

However, you need more than that to overcome the gravitational force. The body is kept from moving straight down by the plane, so it would only go down the plane with a force of (16 kg)*(9.8 m/s^2)cos 30 degrees. Reverse that force and add to the above ("NET").

Now, I may have made a mistake somewhere, so go over that solution carefully. Don't blame me, it was a rush job, right, boss? :smile:
 
nutzweb said:
what force, applied parallel to the plane, is necessary to move a 16 kg object up africtionless palne with a uniform acceleration of 2.0 m/s2 if the plane makes an angle of 60 degrees with the horizontal?
The component of the object's weight parallel to the plane is mg\sin\theta acting down the plane. The applied force F (acting up the plane) must be enough to overcome that and produce the needed acceleration:
F = mg\sin\theta + ma
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top