How Much Ice Melts from a Sliding Block's Kinetic Energy?

AI Thread Summary
A 2.5 kg block of ice at zero degrees Celsius slides with an initial speed of 5.7 m/s, and the problem involves determining how much ice melts when its kinetic energy is converted to internal energy. The kinetic energy (KE) of the block is calculated using the formula KE = 0.5mv², resulting in 41 J. To find the mass of ice melted, this energy is divided by the energy required to melt 1 kg of ice, which is 3.3 x 10^5 J. The calculation yields approximately 0.0000124 kg of melted ice. The solution is confirmed as correct by participants in the discussion.
chops369
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Homework Statement


A 2.5 kg block of ice at a temperature of zero degrees celcius and an initial speed of 5.7 m/s slides across a level floor. If 3.3 x 105 J are required to melt 1 kg of ice, how much ice melts, assuming that the initial kinetic energy of the ice block is entirely converted to the ice's internal energy?


Homework Equations


I think I need to use PE + KE + U = 0


The Attempt at a Solution


I have no idea where to even begin :(
 
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chops369 said:

Homework Statement


A 2.5 kg block of ice at a temperature of zero degrees celcius and an initial speed of 5.7 m/s slides across a level floor. If 3.3 x 105 J are required to melt 1 kg of ice, how much ice melts, assuming that the initial kinetic energy of the ice block is entirely converted to the ice's internal energy?


Homework Equations


I think I need to use PE + KE + U = 0


The Attempt at a Solution


I have no idea where to even begin :(

Well the formula for kinetic energy of a body is KE = .5mv2. So how much kinetic energy do we have in the block at the start? If you assume all of that gets transferred into heat energy how much ice did it melt?
 
Ok, so I used KE = .5mv2 and found that the ice has an initial KE of 41 J. Then I did 41 / 3.3 x 105 and I concluded that .0000124 kg of ice melted. Is this correct?
 
chops369 said:
Ok, so I used KE = .5mv2 and found that the ice has an initial KE of 41 J. Then I did 41 / 3.3 x 105 and I concluded that .0000124 kg of ice melted. Is this correct?

Sounds correct to me.
 
Great, thanks a lot.
 

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