How much magnesium is needed to react with oxygen gas at specified conditions?

AI Thread Summary
Magnesium reacts with oxygen gas to form magnesium oxide, and the discussion revolves around calculating the mass of magnesium needed for a specific volume of oxygen at given conditions. To solve the problem, the ideal gas law (PV=nRT) is suggested to determine the amount of oxygen gas available. Three potential solutions for the mass of magnesium are proposed: 0.945 g, 0.418 g, and 0.124 g. Participants are encouraged to share their calculations and the balanced chemical equation for the reaction to assist in identifying the correct solution. Collaborative problem-solving is emphasized to reach the accurate answer.
bluegirlbalance
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Magnesium burns in oxygen gas to produce magnesium oxide. What mass of magnesium will react with a 0.25 L container of oxygen gas at 80oC and 770 mmHg? :confused:



I need to use stoichiometry to set up the pronlem and PV=nRT to solve.

I have three possible solutions, but I don't know which one is the correct one. The solutions I have are .945 g, .418 g, and .124 g.
 
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Have you done any work on this problem? If you show work we can help you through the problem. Do you have the equation of the reaction?
 
Use PV=nRT to calculate amount of oxygen.
 
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