How Much Power Should an LED Emit to Be Visible from 5 Meters?

AI Thread Summary
To determine the power an LED must emit to be visible from 5 meters, one must calculate the energy required for 100 photons at a wavelength of 5500Å to reach the human eye in one second. Each photon carries energy calculated using E=hc/lambda, where h is Planck's constant and c is the speed of light. The solid angle of the eye's pupil, approximately 15mm in diameter, must be considered to estimate how many photons will hit the pupil. Assuming the LED emits light uniformly in all directions, the necessary power can be derived from the energy needed and the solid angle. The discussion concludes with the realization that these calculations will yield the required LED power for visibility.
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Homework Statement


In ideal conditions human eye can feel something if 100 photons with wavelengh of 5500A fall directly tu human eye in one seconds time.LED(lambda=5500A) is placed 5m away from human eye.


Homework Equations



Calculate the power of LED to achieve that the human eye can see it?

The Attempt at a Solution

 
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What is your difficulty?
 
I even don't know where to start here.
Some kind of idea would be helpfull.
 
Each photon carries energy. How much?
 
I know that much
E=hv and v=c/lambda so E=hc/lambda
 
So you should be able to solve the problem.
 
You also need to know how many photons miss or hit the pupil. Perhaps they all bit because of lenses. Or not.
 
Ok I know the energy which is needed to feel something.
I assume that all hit the pupil and that diameter of an eye is d=15mm.
So i can calculate the solid angle.

But still how can I calculate power of LED ?
 
I think you can assume that the LED radiates in all directions. You have a particular solid angle where particular energy must be radiated to be be detectable. What else do you need?
 
  • #10
OK,thanks.
I think i got it.
 
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