How Much Vertical Acceleration Does a Jet Need to Avoid a Hill?

AI Thread Summary
To avoid colliding with a hill, a jet traveling at 1300 km/h and 35 meters above ground must achieve a vertical acceleration of 10 m/s². The problem involves calculating the necessary upward acceleration to ensure the jet clears a 10% slope. It is suggested to visualize the jet's trajectory through a diagram to understand the required adjustments. The key equations involve the jet's position over time and the relationship between its vertical acceleration and trajectory. Understanding these dynamics is crucial for determining the minimum acceleration needed to prevent impact.
KukyZ
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New user has been reminded to please always show their work on schoolwork problems.
Homework Statement
A jet travels at speeds of 1300 km/h at 35 m above ground level. Suddenly it meets a slope of 10% and immediately corrects its trajectory accelerating upwards (a(t) constant, in the direction of y).
How much should the acceleration be worth to avoid impact with the ground?
Relevant Equations
x=V
y=35+1/2 at^2
The answer should be 10 m/s^2 but I don't know how to solve it
 
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I guess you meant x=vt.
So you have the position of the jet at time t. What about the position of the ground below it?
 
KukyZ said:
Homework Statement: A jet travels at speeds of 1300 km/h at 35 m above ground level. Suddenly it meets a slope of 10% and immediately corrects its trajectory accelerating upwards (a(t) constant, in the direction of y).
How much should the acceleration be worth to avoid impact with the ground?
Relevant Equations: x=V
y=35+1/2 at^2

The answer should be 10 m/s^2 but I don't know how to solve it
I suspect that the problem is asking for the smallest possible vertical acceleration that will prevent a collision with the ground. Start by drawing a diagram of the jet's trajectory. The jet must barely graze the hillside.

How do you know that the answer is 10 m/s2?
 
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