How Much Work for a Chin-Up Based on Body Mass?

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To calculate the work done during a chin-up, the formula Us = mgh is applied, where 'm' is the mass, 'g' is the acceleration due to gravity, and 'h' is the height lifted, which is 0.40 m. For part (a), the work done per kilogram of body mass can be determined using the given height. In part (b), the percentage of body mass that the muscles constitute is calculated based on the work output of 70 J per kilogram of muscle mass. Part (c) requires a similar calculation for the man's son, considering his shorter arm length but the same muscle efficiency. The discussion highlights the importance of understanding physical principles to solve the problem effectively.
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Homework Statement



While doing a chin-up, a man lifts his body 0.40 m.



Homework Equations



Us = mgh
W = Fd

a) How much work must the man do per kilogram of body mass?

b)The muscles involved in doing a chin-up can generate about 70 J of work per kilogram of muscle mass. If the man can just barely do a 0.40-m chin-up, what percentage of his body's mass do these muscles constitute? (For comparison, the total percentage of muscle in a typical 70-kg man with 14% body fat is about 43%.)

c)Repeat part (b) for the man's young son, who has arms half as long as his father's but whose muscles can also generate 70 J of work per kilogram of muscle mass.


I have no clue how to begin. It seems they only provided me with \DeltaX = .40m
 
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Hi Chandasouk! :smile:

(have a delta: ∆ :wink:)
Chandasouk said:
… I have no clue how to begin. It seems they only provided me with \DeltaX = .40m

Yes, they have … they've also provided you with the mass (because everything is per kilogram). :wink:
 
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