How Much Work is Done Pushing a Crate Up a Plank?

  • Thread starter Thread starter lilmissbossy
  • Start date Start date
  • Tags Tags
    Mass Work
AI Thread Summary
The discussion focuses on calculating the work done in pushing a crate up a plank and the increase in potential energy (PE) once the crate is on a platform. The work done is calculated using the formula W=Fxd, resulting in 2450 N. The increase in potential energy is determined using PE=mgh, yielding a value of 1176 N. The calculations assume no friction and that the force is applied along the length of the plank. The participant expresses satisfaction with their correct solution.
lilmissbossy
Messages
14
Reaction score
0

Homework Statement


force F is required to push a crate of mass m up a plank of length L into a truck whose platform is a vertical distance h above the road.

a)How much work is done pusing the crate up the plank m=100kg, L=5m, F=490N h=1.2m
b)what is the increase in PE of the crate once the crate is on the platform


Homework Equations


W=Fxd
PE=mgh



The Attempt at a Solution



ok so my working is

W=Fxd
W=490Nx5m
W=2450N

and

PE=mgh
PE=(100kg)(9.8ms-1)(1.2m)
PE=1176 N

Hmmmmmmm...i think they are right
 
Physics news on Phys.org
Yeah it looks ok, provided no friction is involved and F is directed along the length of L.
 
Excellent i finally got one right by myself!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top