How Much Work Is Required to Move a Refrigerator Across a Frictional Surface?

Thread starter physicos
Start date Mar 21, 2014
Tags

Energy Kinetic Kinetic energy Work

AI Thread Summary

To move a 100 kg refrigerator across a frictional surface with a friction force of 200 N for 6 meters, the work required is calculated using the equation W(T) = f * Δl. The user determined the work needed to be 1200 J. The calculations appear to be correct based on the provided equations. The discussion confirms that the work done against friction is the primary factor in this scenario. The conclusion is that 1200 J is indeed the correct amount of work required.

Mar 21, 2014

physicos

Homework Statement

A 100 kg refrigerator is on rest on the floor.How much work is needed to move the refrigerator at a constant speed for 6 m along with a floor friction force of 200 N ?

Homework Equations

I used ΔK = W(F_g)+ W (N) + W(f)+ W(T) =0
and W(F_g)+ W (N) = 0
so W(T)=-W(f)=f* Δl

The Attempt at a Solution

The needed work is W(K)= 1200 J

Is it correct ??

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Mar 21, 2014

Rellek

Looks correct to me!

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