How much work was done aginst friction?

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The discussion revolves around calculating the work done against friction, gravity, and total work for a block being pushed up a ramp. The user has determined the angle of the ramp to be 19 degrees and calculated the total work done as 91 Joules. To find the work against gravity, the user is advised to use the formula mgh, resulting in 150 Joules for a height of 2 meters. The work against friction can be found by subtracting the work against gravity from the total work. Power developed can be calculated using the formula P=FV, where F is the force required to move the block and V is the given velocity.
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Hello I am having toruble solving this problem. I would appreciate any help.

A 75 N block is pushed at 5.0 m/s up a ramp 6.0 m long to a platform 2.0 m high. If the coefficient of friction is 0.300
a) how much work was done?
b) how much work was done aginst friction?
c) how much work was done against gravity?
d) how much power was developed?

I solved for theta using trig and got 19 degrees.
Then I solved for work with the equation [Fw(sintheta+ucostheta)]h and got 91J.
I am confused on how to solve for the work against friction and the work aginst gravity though.
Thanks for any help
 
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ok here is the way to proceed

first draw the free body diagram for it

you will get the following things from it
1) weight mg(75 N) acting downwards
2) then normal reaction mgcos(teta)
3) the force 0.3*R(normal reaction)

now solve for it using
w=f*s
where f is the force required to move up
where s is the distance moved , use trignometry and u will get it
the work according to me is 135J

c)then for the work done against gravity,to reach the topest point u will need mgh J where h is 2 m in ur case

b)from the total work done subtract this and u will get the work done against friction

d) use P=FV
where F is the force to move up and v is velocity given(5 m/s)

hope this helped u. please tell me If i am wrong.
-benzun
 
note keep the trigrometic values in fraction itself don't find the angle
 
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