How much work was done on the mass?

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The discussion revolves around calculating the final velocity and work done on a 1.20 x 10^3-kg block accelerated by a 2.20 x 10^3-N force over 50 meters. The user initially calculated the work done using the formula W=Fd, but received feedback to correct their arithmetic, noting the importance of tracking exponents accurately. For finding the final velocity, suggestions included calculating acceleration first or using the work-energy principle to relate work done to kinetic energy. The conversation emphasizes the correct application of physics formulas and careful arithmetic in problem-solving. Accurate calculations are essential for deriving the correct answers to both parts of the problem.
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Homework Statement


A 1.20 x10^3-kg block starting from rest is accelerated by a 2.20x10^3-N force for a distance of 50.0 meters along a horizontal frictionless surface.

a. What is the final velocity of the mass?

b. How much work was done on the mass?

I have no clue how to get A but for B i just Used W=Fd and got 2.20x10^3-N * 50m =
0.11 (Nm)

Can someone confirm my answer to B and help me with A?

Thanks.
 
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OstralyanPain said:
I have no clue how to get A but for B i just Used W=Fd and got 2.20x10^3-N * 50m =
0.11 (Nm)
Correct formula, but redo that arithmetic. (Keep better track of the exponents.)

For A, either find the acceleration and use kinematics or use the result of part B and relate the work done to the kinetic energy.
 
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