How Should Electric Potential Energy Be Ranked at Point P?

AI Thread Summary
The discussion focuses on ranking electric potential energy at point P for four cases, with the initial belief being U2 > U1 > U3 > U4. The correct ranking is established as U2 > U1 = U3 = U4, based on the relationship between electric potential (V) and electric potential energy (Ue). The potential is defined as the work done by the electric field on a unit positive charge, and it is calculated using the formula V = k(q/r). The conversation highlights the application of Gauss's Law to determine the electric field around a charge and confirms the understanding of potential energy in a conservative field. The final solution is affirmed as correct.
STEMucator
Homework Helper
Messages
2,076
Reaction score
140

Homework Statement



Rank the electric potential energy at point ##P## for the following four cases:

http://gyazo.com/c7d9df3d3d64cda909ddc0d2ab7686bc

Homework Equations



##\Delta U_e = - W_∞##

The Attempt at a Solution



I believe it should be ##U_2 > U_1 > U_3 > U_4##, but I am not certain.
 
Physics news on Phys.org
Why do you think what you believe? How is electric potential defined? And what is the electric potential at distance r from a point charge q?

ehild
 
  • Like
Likes 1 person
ehild said:
Why do you think what you believe? How is electric potential defined? And what is the electric potential at distance r from a point charge q?

ehild

Ah I see, so ##V = k \frac{q}{r}## in combination with ##V = \frac{U_e}{q}##.

This yields ##U_2 > U_1 = U_3 = U_4##.

Thank you.
 
Zondrina said:
Ah I see, so ##V = k \frac{q}{r}## in combination with ##V = \frac{U_e}{q}##.

This yields ##U_2 > U_1 = U_3 = U_4##.

Thank you.

The solution is correct now.

Yes, the potential is the potential energy of a unit positive charge at a certain point of the electric field. It is defined with the work done by the field:
The potential at a point P is equal to the work done by the electric field on a unit positive charge while it moves from P to the place where the potential is zero.

You know from Gauss Law that the electric field around a charge q is E=kq/r2. It is a conservative field. The potential U(r_P) is the work on a unit positive charge when it moves from rP to infinity: U(r_P)=W\big |_{r_P}^{\infty}=\int _{r_P}^{\infty}{\frac{kq}{r^2}dr}=k\frac{q}{r_P}.

ehild
 
  • Like
Likes 1 person
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top