# How should i do this?

1. Oct 24, 2004

### Chris-is-stuck

hi im sorry this is probably going to seem very easy to all you viewers but up to this point ive had to teach myself physics because i had no teacher. i still got a* at gcse though :tongue2:

the question is: A cell of negligible resistance is connected in a series with a microammeter of negligible resistance and two resistores of 10 ohms and 15 ohms. The current is 200 uA.

Calculate the EMF of the cell.

thanks alot to anyone to helps me with this, cya later.

(jsut read rules sorry if ive broken any)

Last edited: Oct 24, 2004
2. Oct 24, 2004

### James R

The total resistance is R=10+15=25 ohms. Therefore:

EMF = iR

You have i, so...