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niravana21
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Homework Statement
Please find the anti-derivative of 1/sin(x) + cos(x) dx
Homework Equations
csc(x)dx = -ln[csc(x) + cot(x)] + C
Thanks. Been at it for a while now.
Cyosis said:I am confused, you are given the primitive of the cosecant and you do not know how to integrate the cosecant+ the cosine? Or do you need to derive the primitive for the cosecant as well?
Or in other words, the integrand is 1/(sin(x) + cos(x)).niravana21 said:Sorry it was my mistake. Its 1 over the sin and cos
Mark44 said:Or in other words, the integrand is 1/(sin(x) + cos(x)).
Parentheses are especially important when you're writing algebraic expressions on what is essentially a single line.
By writing 1/sin(x) + cos(x), most people would correctly interpret this as
[tex]\frac{1}{sin(x)} + cos(x)[/tex]
even though that's not what you intended.
niravana21 said:yes i get it, but this has in no way helped me answer the question.
niravana21 said:yes i get it, but this has in no way helped me answer the question.
Mark44 said:But it made it harder for people on this forum to understand exactly what you were asking. The way you wrote it confused Cyosis, although Dick was able to translate what you wrote into what the problem actually was. My post was aimed at getting you to realize the importance of writing your problems so that people can easily understand them.
niravana21 said:yes i realized that, so i quickly posted that it is 1 over the sin and cos.
To anti-differentiate 1/sin(x) + cos(x), you can use the following steps:
Yes, you can simplify the expression 1/sin(x) + cos(x) before anti-differentiating. You can use the trigonometric identity csc(x) = 1/sin(x) to rewrite the expression as 1/sin(x) + cos(x) = csc(x) + cos(x).
The anti-derivative of 1/sin(x) is -ln|csc(x) + cot(x)| + C, where C is the constant of integration.
Yes, you can use substitution to anti-differentiate 1/sin(x) + cos(x). You can let u = sin(x) and du = cos(x)dx, then the expression becomes 1/u + du. You can then use the power rule of differentiation to find the anti-derivative of 1/u and du, and combine the two results to get the anti-derivative of 1/sin(x) + cos(x).
Yes, there are other methods for anti-differentiating 1/sin(x) + cos(x). You can use integration by parts, trigonometric identities, or partial fractions to find the anti-derivative of the expression. However, using substitution or the power rule of differentiation is usually the simplest method for this expression.