How to Approach the Integration of Complex Functions with Limits from -3 to 3?

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Homework Help Overview

The discussion revolves around the integration of a complex function defined as ( (sqrt (x^2 - 9))/x )( exp x^2 )( cos 7x )( sin(x^4 + 5x^2 + 100) ) dx, with limits from -3 to 3. Participants explore the challenges associated with finding a closed-form solution and consider numerical integration as an alternative.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of integration by parts and express uncertainty about integrating specific components of the function. Some question the feasibility of finding a closed-form antiderivative, while others suggest contemplating numerical methods. There are inquiries about the implications of symmetry in the integration process and the conditions under which it can be applied.

Discussion Status

The discussion has evolved with participants sharing insights about symmetry and the potential cancellation of areas under the curve. Some have proposed proving properties of the function related to oddness, while others emphasize the need to verify the function's behavior within the specified limits. There is no explicit consensus on a solution, but various lines of reasoning are being explored.

Contextual Notes

Participants note the complexity of the integrand and raise concerns about its definition within the integration limits, particularly regarding the presence of a fraction and the behavior of the sine function in the denominator.

lap
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Integrate ( (sqrt (x^2 - 9))/x )( exp x^2 )( cos 7x )( sin(x^4 + 5x^2 + 100) ) dx
with upper limit = 3 and lower limit = -3

I have tried to use integration by part and set u = ( (sqrt (x^2 - 9))/x )( exp x^2 ) and
dv = ( cos 7x )( sin(x^4 + 5x^2 + 100) ) dx
 
Last edited:
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What have you tried so far?
 
lap said:
Integrate ( (sqrt (x^2 - 9))/x )( exp x^2 )( cos 7x )( sin(x^4 + 5x^2 + 100) ) dx
with upper limit = 3 and lower limit = -3

I have tried to use integration by part and set u = ( (sqrt (x^2 - 9))/x )( exp x^2 ) and
dv = ( cos 7x )( sin(x^4 + 5x^2 + 100) ) dx

But I don't know how to integrate the dv

I very much doubt there is any closed-form formula for the antiderivative, so you probably need to contemplate numerical integration for the general case of ##\int_a^b f(x) \, dx##. However, before doing that, sit down and think carefully about your specific problem.
 
How to integrate ( (sqrt (x^2 - 9))/x )( exp x^2 )( cos 7x )( sin(x^4 + 5x^2 + 100) ) dx ?
 
lap said:
How to integrate ( (sqrt (x^2 - 9))/x )( exp x^2 )( cos 7x )( sin(x^4 + 5x^2 + 100) ) dx ?

I have already told you it cannot be done with formulas---even very long ones having billions of complicated terms and taking millions of pages to write out. However, that was not your original question: you wanted ##\int_{-3}^3 f(x) \, dx##. As I suggested, think hard about the problem first.
 
The answer is 0 ?
 
The answer is correct but can you prove it?
 
I know the answer is 0 because the positive area canceled the negative area but I don't know how to prove it
 
lap said:
I know the answer is 0 because the positive area canceled the negative area but I don't know how to prove it

If f(x) is that big expression you are integrating, can you prove that f(-x)=(-f(x))? Then show ##\int_{-a}^0 f(x) dx = -\int_{0}^a f(x) dx##.
 
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  • #10
I proved that f(-x)=(-f(x)) and solved it. Thank you very much !
 
  • #11
In order to use symmetry here you must also show that this is not an improper integral. Your integrand is a fraction with sin(x^4+ 5x^2+ 100) in the denominator. Can you show that this never 0 for x between -3 and 3?
 
  • #12
HallsofIvy said:
In order to use symmetry here you must also show that this is not an improper integral. Your integrand is a fraction with sin(x^4+ 5x^2+ 100) in the denominator. Can you show that this never 0 for x between -3 and 3?

There is an x in the denominator instead of sine. Moreover, the function doesn't seem to defined within the given limits.
 

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