How to Calculate Capacitance for Two Slanted Conducting Plates?

AI Thread Summary
To calculate the capacitance of two slanted conducting plates, the formula C = (εA)/d is used, where A is the area and d is the distance between the plates. The discussion highlights the need to determine the effective distance d' for the slanted plate, which varies along its length. A strip of the plate is considered for integration, with the capacitance of that strip expressed as ΔC = εο*L*dx/(d + d'). The participants note discrepancies in the numerical values provided, specifically regarding the distances between the plates at different points. Accurate calculations require careful consideration of the angles and distances involved in the geometry of the setup.
blackblanx
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Homework Statement



Determine the capacitance of two conducting plates facing each other at an angle as shown (in link) . Plate A and B have dimensions of 10x20 cm and 10x (20sec30) (angles in degrees)

Homework Equations


C=( \epsilon A)/d


The Attempt at a Solution


not quite sure can someone help me get the ball rolling or the floor moving
 

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If you take one strip of the plate of width dx and length L.
The capacity of that strip is given by
ΔC = εο*L*dx/(d + d')
From the figure write down d' in terms of x and θ.
Find the integration to get the capacitance C.
 
What are you using for d' ?
 
blackblanx said:
What are you using for d' ?
d' is the variance distance of the slanted plate from the horizontal line.
In the problem, numerical values are not correct.
One end of the slanted plate is 1 mm from the top plate,. And the other end is 0.1 mm from the top plate. So tan θ = 0.9 mm/0.1 mm which is not equal to tan(30)
 

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