How to Calculate Energy Stored in an RLC Circuit?

AI Thread Summary
To calculate the energy stored in an RLC circuit, first determine the charge on the capacitor using the formula Q = CV, where C is the capacitance and V is the voltage. For a 21.0 μF capacitor charged to 160.0 V, the initial charge is 3.36 mC. The energy stored in the capacitor at t = 0 ms can be calculated using U = 0.5 * CV^2, resulting in 0.5376 joules. At t = 1.30 ms, the energy stored in the inductor can be calculated using the current derived from the oscillation equations, specifically U = 0.5LI^2, where L is the inductance. Understanding these calculations is essential for analyzing energy transfer in RLC circuits.
danbone87
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Homework Statement



A 21.0 \mu F capacitor is charged by a 160.0-{\rm V} power supply, then disconnected from the power and connected in series with a 0.220-{\rm mH} inductor.

Calculate the energy stored in the capacitor at time t = 0{\rm{ ms}} (the moment of connection with the inductor).

Calculate the energy stored in the inductor at t = 1.30 ms.

Homework Equations



i=-omegaQsin(omega*t)

and U=.5LI^2

I need to either find charge q or a resistance value to find I with and I'm stuck..
 
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Hi danbone87,

danbone87 said:
A 21.0 \mu F capacitor is charged by a 160.0-{\rm V} power supply,

The way the capacitor is initially connected by itself to the battery will give you its initaial Q value.

danbone87 said:
I need to either find charge q or a resistance value to find I with and I'm stuck..

If I'm reading the problem correctly, there is no resistor; just a capacitor connected to an inductor.
 
A 21.0 \mu F capacitor is charged by a 160.0-{\rm V} power supply, then disconnected from the power and connected in series with a 0.220-{\rm mH} inductor.

Calculate the energy stored in the capacitor at time t = 0{\rm{ ms}} (the moment of connection with the inductor).

Calculate the energy stored in the inductor at t = 1.30 ms.ans= q=cv=22u*160m gives u charge
energy=.5*22u*160m*160m=1/2(c*v*v)
now
VL=Ldi/dt
 
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