How to Calculate Gauge Pressure to Compress Water?

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To calculate the gauge pressure required to compress pure water from 1.000 L to 989 mL, the bulk modulus of water, which is 2.2 x 10^9 N/m^2, is used in the formula B = ΔP/(ΔV/V). The necessary gauge pressure can be expressed in both N/m^2 and psi. Additionally, the height of a steel bar needed to exert this pressure can be determined using its density of 7.86 g/cm^3. Finally, the total weight of steel required to exert this pressure on one cubic face of a liter of water can also be calculated.
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I have tried and tried to figure this out but I'm getting no where. Can anyone help me?

(a) Calculate the gauge pressure (it does not include atmosphereric P) required to compress pure water from 1.000 L to 989 mL. Give an answer in both N/m^2 and psi, lb/in^2.

(b) What height in meters and feet of a 1x1 cm^2 steel bar (density=7.86 g/cm^3) is required to exert the pressure found in part (a)?


(c) How many total pounds of steel would be required to exert this pressure on one cubic face of a liter of water (1 L= 1 cubic decimeter)?
 
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a. Use the formula for bulk modulus. B = delta P/(delta v)/v. B for water is 2.2*10^9 N/m^2.

I hope the other answers will follow.
 
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