How to Calculate Height of a Cliff Based on Falling Object Time?

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To calculate the height of a cliff based on the time it takes for a stone to fall, the correct formula is x = 1/2 a t², where 'a' is the acceleration due to gravity (9.8 m/s²) and 't' is the time in seconds (3.25 s). The initial velocity (Vo) is zero since the stone is dropped. The equation V² = Vo² + 2a(X - Xo) is not appropriate for this scenario, as it misinterprets the time as velocity. Using the correct formula, the height can be accurately determined. This method is essential for solving basic kinematics problems involving free fall.
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Greg Bernhardt said:
Author: Dr. Donald Luttermoser of East Tennessee State University

i have a quetion for you Dr., I know this is a simple problem but my physics book is not very clear on how to figure out this answer to the question. "A stone dropped from the top of a cliff. it hits the ground below after 3.25s. how high is the Cliff?"
*to figure this out do you not use this equation? V^2 =Vo^2+ 2a(X-Xo)* a=9.8m/s, V=3.25s, initial V=0, X=?
 
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ldbaseball16 said:
i have a quetion for you Dr., I know this is a simple problem but my physics book is not very clear on how to figure out this answer to the question. "A stone dropped from the top of a cliff. it hits the ground below after 3.25s. how high is the Cliff?"
*to figure this out do you not use this equation? V^2 =Vo^2+ 2a(X-Xo)* a=9.8m/s, V=3.25s, initial V=0, X=?

I might point out a couple of things. First the post you have tagged is 3 years old. And it it a tutorial about kinematics in 1 dimension.

Second the problem you related suggests that the time to the bottom of the cliff is 3.25 seconds. This would not be a good thing to substitute directly as Velocity.

If you know gravity (9.8 m/s2) and you know time then the correct relationship would be x = 1/2 a t2
 
thank you DR
 
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