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change in her angular speed? What is the change in her kinetic energy? Explain this change

in kinetic energy.

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- Thread starter davidraj
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- #1

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change in her angular speed? What is the change in her kinetic energy? Explain this change

in kinetic energy.

- #2

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- #3

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A bus is moving downhill at a slope of 5°. At the moment when the speed of the bus is

30 km/h, the driver spots a deer 30m ahead. He applies the brakes and comes to a stop. The deer is paralyzed by fear and does not move. Will the bus stop before reaching it or will it hit the deer? Do relevant calculations and draw appropriate force diagram. Take the coefficient of kinetic friction to be µk = 0.26.

I calculated the velocity of the bus when it reaches the deer using the formula, Work done = 1/2 mv1 square - 1/2 mv2 square....where work done is given by -µ . m . g . d....the velocity of the bus comes around 27 km/h when it reaches the deer...is my equation correct? if not kindly suggest the method of solving this question...

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A plane is flying with a constant speed along a straight line at an angle of 60° with the

horizontal. The weight W of the plane is 90, 000 N and its engine provides a thrust T of

120, 000 N in the direction of flight. Two additional forces are exerted on the plane: the lift force F perpendicular to the plane’s wings, and the force R due to air resistance opposite to the direction of motion. Determine F and R.

Can you kindly tell me what steps and formulae should be used to calculate F and R?

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Can you draw a free body diagram showing all forces?

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O is the startin point. OT gives the direction and magnitude of Thrust. RP stands for the resistance of air ( drag?) . FP is the Force (Lift) that acts perpendicular to the wings. Am sure I've got one or two of these wrong. Kindly correct.

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Vertical forces are the Force of Lift and the weight of the plane acting opposite to each other. Bur how do i derive an equation based on this statement?

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