How to Calculate Kinetic Energy Percentage in Non-Elastic Collision?

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SUMMARY

The discussion focuses on calculating the percentage of kinetic energy retained by a target after a non-elastic collision with a projectile. In this scenario, a projectile with a mass of 0.20 kg embeds itself into a target with a mass of 2.50 kg. Since this is a non-elastic collision, kinetic energy is not conserved, and the energy is transformed into other forms. The key takeaway is that the kinetic energy carried off by the target post-collision must be calculated using the principles of momentum conservation and the specific equations governing non-elastic collisions.

PREREQUISITES
  • Understanding of non-elastic collision mechanics
  • Familiarity with the conservation of momentum principle
  • Knowledge of kinetic energy equations
  • Basic algebra skills for calculations
NEXT STEPS
  • Study the conservation of momentum in inelastic collisions
  • Learn how to apply the kinetic energy formula: KE = 0.5 * m * v^2
  • Explore examples of non-elastic collision problems
  • Review the differences between elastic and inelastic collisions
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of collision mechanics and energy transformation in non-elastic collisions.

kbeyer
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Problem: A projectile (mass = 0.20 kg) is fired at and embeds itself in a target (mass = 2.50 kg). The target (with the projectile in it) flies off after being struck. What percentage of the projectiles' incident kinetic energy does the target (with the projectile in it) carry off after being struck?
 
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Energy is conserved. Kinetic energy in an elastic collision (where there is no conversion to any other sort of energy) remains the same.
 
Welcome to PF, kbeyer.

This is not an elastic collision, so kinetic energy is not conserved.

So, what equation or equations do you know that deal with collisions?

edit added:
please post homework questions in the homework area of the forum:
https://www.physicsforums.com/forumdisplay.php?f=153
 

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