How to Calculate Power and Energy Usage in Electrical Devices

  • Thread starter Thread starter johnson.3131
  • Start date Start date
  • Tags Tags
    Power Resistor
Click For Summary
SUMMARY

The discussion focuses on calculating power and energy usage for a blow-dryer and a vacuum cleaner operating at 120 V. The blow-dryer consumes approximately 1.6 kW based on its current rating of 13 A, while the vacuum cleaner consumes 360 W with a current rating of 3.0 A. The ratio of energy used by the blow-dryer in 21 minutes to that used by the vacuum cleaner in 30 minutes is established as 3. This calculation utilizes the equations P = IV and E = Pt for determining power and energy, respectively.

PREREQUISITES
  • Understanding of electrical power calculations using the formula P = IV
  • Familiarity with energy calculations using E = Pt
  • Knowledge of SI units for voltage, current, and time
  • Basic grasp of electrical devices and their specifications
NEXT STEPS
  • Research the implications of power ratings on energy consumption in household appliances
  • Learn about the conversion of time units for energy calculations
  • Explore the impact of voltage and current ratings on appliance efficiency
  • Investigate advanced electrical equations such as R = E^2/P for deeper insights
USEFUL FOR

Electrical engineers, students studying physics or electrical engineering, and anyone interested in understanding energy consumption in household devices.

johnson.3131
Messages
6
Reaction score
0
A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 13 A, and that of the vacuum cleaner is 3.0 A.
(a) Determine the power consumed by the blow-dryer.
1 W

(b) Determine the power consumed by the vacuum cleaner.
2 W

(c) Determine the ratio of the energy used by the blow-dryer in 21 minutes to the energy used by the vacuum cleaner in one-half hour.
Ebd / Evc = 3



Relevant Equations R=E^2/P
I=E/R

I mostly get confusedon what E is and what R is in the problem
 
Physics news on Phys.org
Hello johnson!

I'm afraid I just don't see how you get yours answers for Part a) and b). Here, we could use the equation [tex]P = IV[/tex], so for eg part a), I get approximately 1.6 kW, not 1 W. I think there may be a misunderstanding here.

For part c), Power is the rate of Energy per time, ie [tex]P = E/t[/tex]. Rearrang the equation for E (Energy). We can work out how much energy each item takes by then replacing P with the value we got earlier, and t with the time we are told (remember to convert to SI units). Then we can divide appropriately to get the ratio.

We don't need R anywhere.
 
thanks soo much...i just figured out that I messed up the equations like crazy...i have the right answers now.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
8K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
13
Views
7K
  • · Replies 34 ·
2
Replies
34
Views
4K
  • · Replies 7 ·
Replies
7
Views
7K