How to Calculate Power Generated by Niagara Falls - Help with Power Problem

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To calculate the power generated by the falling water at Niagara Falls, the gravitational potential energy (PE) is determined using the formula PE = mgh, where m is the mass flow rate, g is the acceleration due to gravity, and h is the height. With a mass flow rate of 1.2 x 10^6 kg/s and a height of 50 m, the potential energy calculated is 588,600,000,000 joules. To convert this energy into power, which is measured in watts, the energy must be divided by time, recognizing that 1 watt equals 1 joule per second. Therefore, the power generated can be calculated by using the rate of water flow to find the energy produced per second. This approach effectively translates gravitational potential energy into a power output measurement.
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Homework Statement



water flows over a section of niagara falls at the rate of 1.2*10^6 kg/s (kilograms per second) and falls 50.0 m (meters). How much power is generated by the falling water?


Homework Equations



--none.


The Attempt at a Solution



gravitational potential energy (PE grav)=mgh (mass*gravity*height)
PE grav=(1.2*10^9 g/s)(9.81)(50.0 m)
PE grav=588,600,000,000

but PE is measured in joules. and power is measured in watts. so how do i get from PE to W?
 
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1 Watt = 1 Joule per second
 
You were given the rate in the question. Look at the units in your calculation.
 
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