How to Calculate the Current Flowing Through a Gold Wire?

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The discussion centers on calculating the current flowing through a gold wire connected to a 0.70 V battery. The user calculated the resistance using the resistivity of gold and found the current to be 3.57 mA, but this answer was marked incorrect in MasteringPhysics. Participants suggested that the resistivity value used might not align with what the platform expects, emphasizing the importance of significant figures in the final answer. They noted that the expected current should be around 3.5 mA, indicating a possible discrepancy in the resistivity value or calculation method. The issue may stem from the platform's strict requirements or an error in the question itself.
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Homework Statement


The terminals of a 0.70 Vwatch battery are connected by a 70.0-m-long gold wire with a diameter of 0.100 mm.
What is the current in the wire?

Homework Equations


V = IR
R = pL/a

The Attempt at a Solution



I try to find resistance first, resistivity of gold is 2.2 * 10 ^-8

Area of the wire is a = pi * r ^ 2
r = ( 0.1 * 10^-3 ) /2

So I found a = 7.85 * 10^-9

Then,
R = 2.2 * 10^-8 * 70 / (7.85 * 10^-9) = 196.1

I plug this into V/R = I, .70/196.1 = .00357 = 3.57 mA, but this answer ends up being wrong. Any help on where I went wrong would be appreciated, thanks.
 
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mfb said:
WolframAlpha agrees. Why do you think it is wrong?
I'm putting exactly 3.57 mA into MasteringPhysics, but it keeps saying my answer is incorrect. http://imgur.com/SZN22sv is an image of what the question is, did I type anything wrong? http://imgur.com/pl1MQbC here are the answers I have already tried.
 
david12445 said:

Homework Statement


The terminals of a 0.70 Vwatch battery are connected by a 70.0-m-long gold wire with a diameter of 0.100 mm.
What is the current in the wire?

Homework Equations


V = IR
R = pL/a

The Attempt at a Solution



I try to find resistance first, resistivity of gold is 2.2 * 10 ^-8

Area of the wire is a = pi * r ^ 2
r = ( 0.1 * 10^-3 ) /2

So I found a = 7.85 * 10^-9

Then,
R = 2.2 * 10^-8 * 70 / (7.85 * 10^-9) = 196.1

I plug this into V/R = I, .70/196.1 = .00357 = 3.57 mA, but this answer ends up being wrong. Any help on where I went wrong would be appreciated, thanks.
Where does that value for resistiviuty of gold come from?
 
I searched online for the value of the resistivity of gold wire
 
Does Mastering Physics provide a reference table of constants to use? Perhaps they have a value for the the resistivity of gold that they expect you to use. The value that you found has just two significant figures and you're told to supply a result with three. This could make a difference in your least significant figure.
 
gneill said:
Does Mastering Physics provide a reference table of constants to use? Perhaps they have a value for the the resistivity of gold that they expect you to use. The value that you found has just two significant figures and you're told to supply a result with three. This could make a difference in your least significant figure.

No, I don't think there is one. I tried a value to three significant figures, 2.25 * 10^-8 but it still wasn't right. MasteringPhysics is usually pretty good about saying it's right as long as you are close, so that must mean my answer is a good bit off. Are there any numbers I put in wrong?
 
The value should be in the neighborhood of 3.5 mA. Using various values I've seen for the resistivity of gold I get a range from about 3.51 mA to 3.55 mA.

Could be the question is "broken" in Mastering Physics.
 
Mastering Physics is a stickler for significant figures. Your textbook has a table of resistivities.
 
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