How to calculate the enthelpy change of a neutralization reaction

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To calculate the enthalpy change of a neutralization reaction, such as between NaOH and HCl, the formula used is delta H = [products] - [reactants]. The enthalpy of neutralization for a strong acid and strong base is typically around -13.7 Kcal. However, calculations can vary based on data sources, with one example yielding -43 Kcal/mol. Accurate calculations require knowledge of the enthalpy of formation for each compound involved. Starting from standard elements in their most stable state is essential for precise results.
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Chemistry Help-Enthalpy

Hi. I would very much like to know how to calculate the enthalpy change of a neutralization reaction, for example, NaOH(aq) and HCl(aq).
Thank you very much.
 
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stargazer said:
Hi. I would very much like to know how to calculate the enthalpy change of a neutralization reaction, for example, NaOH(aq) and HCl(aq).
Thank you very much.

Strong acid + strong base has an enthalpy of neutrailzation = -13.7 Kcal

which is the case here
 
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Start from the standard elements in their most stable state at standard conditions. Unless the enthalpy of formation for each compound is provided to you already, it can be a bit complex. Here is an example...

http://groups.msn.com/GeneralChemistryHomework/general.msnw?action=get_message&mview=0&ID_Message=116&LastModified=4675466454162512526
 
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