How to Calculate the Volume of Hydrogen Gas from Liquid State?

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To determine the volume of 277 liters of liquid hydrogen with a mass of 19.7 kg when converted to gas at 25 degrees Celsius and 1 atm, the ideal gas law (PV = nRT) is applied. The ideal gas constant R is typically taken as 0.0821 L-atm/mole-K, though some prefer a more precise value of 0.082057. The mass of hydrogen must first be converted to moles using the molecular weight of H2 (2.0158 g/mol), and the temperature must be converted to Kelvin. The transition from liquid to gas does not affect the number of moles, allowing for volume predictions based solely on the gas law. The calculated volume is approximately 2.39 x 10^5 liters, confirming the application of the ideal gas law in this scenario.
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If 277 L of LIQUID hydrogen has a mass of 19.7 kg, what volume will this amount of hydrogen occupy as a GAS at 25 degrees celcius and 1 atm?



Is there some kind of equation that I can use to make this problem easier?

THANKS!
 
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PV = nRT

You'll use this equation for almost every gas problem.

R (ideal-gas constant) = 0.0821 L-atm/mole-K
V = volume (L)
P = pressure (atm)
n = amount (moles)
T = temperature (K)

V = nRT/P

You need to convert the 19.7 kg H2 to moles H2 and the 25 C to Kelvin.

If you need more help, go ahead and ask.
 
Do you have to take into account the hydrogen beginning as a LIQUID and ending as a GAS?
 
No because when you go from a liquid to a gas, the number of moles of H2 will still stay the same and therefore you can predict the volume.
 
When converting 19.7 Kg to moles would you use H2 (being 2.0158g) or just H (being 1.0079g)?
 
Good question. Always use the diatomic molecule...so H2.
 
Thanks for your help. So if i have done things right my answer should be close to 2.39 X 10^5 L :smile:
 
Yes I got a similar answer. By the way, what value are you using for R? 0.0821 or something more precise?
 
For this problem I just used 0.0821, but usually I use 0.082057
 
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