How to Calculate Torque for Rotating a Supported Vertical Load?

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To calculate the torque required to rotate a supported vertical load, the formula τ = Iα is essential, where τ is torque, I is the moment of inertia, and α is angular acceleration. For a stepper motor operating at 100Hz, the initial angular acceleration can be calculated as 1.57 rad/s², with the angular velocity reaching π/2 rad/s. It's crucial to consider both the frictional force from the thrust bearing and the weight of the load, as torque is also influenced by these factors. The simplified torque equation can be expressed as T = F·R, where F is the weight and R is the horizontal distance from the pivot. Properly accounting for these variables will ensure accurate torque calculations for robotic applications.
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Hi I am designing a 3 axis robot but need help with one calculation.

How do you calculate the torque required to rotate a supported vertical load.

For instance the torque required to rotate a dead weight sitting on top of a thrust bearing. I am looking for some formula from mechanical design books but haven't found anything.

Sorry about asking such a basic question.

Regards,
Tim
 
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thesnesinator said:
Hi I am designing a 3 axis robot but need help with one calculation.

How do you calculate the torque required to rotate a supported vertical load.

For instance the torque required to rotate a dead weight sitting on top of a thrust bearing. I am looking for some formula from mechanical design books but haven't found anything.

Sorry about asking such a basic question.

Regards,
Tim

Welcome to the PF, Tim. The equation you are looking for is:

\tau = I \alpha

Where tau is the torque, alpha is the angular acceration in radians/s^2, and I is the Moment of Inertia:

http://en.wikipedia.org/wiki/Moment_of_inertia

.
 
Thanks Berkeman,

If I'm using a Stepper motor that has an input pulse of 100Hz (90 degrees a second in this setup) is my initial acceleration 1.57 rad per second^2?
 
thesnesinator said:
Thanks Berkeman,

If I'm using a Stepper motor that has an input pulse of 100Hz (90 degrees a second in this setup) is my initial acceleration 1.57 rad per second^2?

If the motor swings 90 degrees in a second, that is an angular velocity omega:

\omega = \frac{\pi}{2} radians per second.

The acceleration would be during the time it takes to go from omega = 0 to omega = PI/2 rad/s. The angular acceleration is the change in the angular velocity with respect to time.
 
thesnesinator said:
Hi I am designing a 3 axis robot but need help with one calculation.

How do you calculate the torque required to rotate a supported vertical load.

For instance the torque required to rotate a dead weight sitting on top of a thrust bearing. I am looking for some formula from mechanical design books but haven't found anything.

Sorry about asking such a basic question.

Regards,
Tim

Don't forget to include the frictional force from the thrust bearing.

http://www.roymech.co.uk/Useful_Tables/Tribology/Plain_Bearing Friction.html

CS
 
Umm, don't forget to in include the weight either T = F.R . Which would be the "torque required to rotate a supported vertical load" as described in the first thread. Where F is the weight of the item and R is the horizontal radius of the load from the pivot position (without acceleration).
 
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