How to Calculate Unit Vector for Mountain Contourlines?

AI Thread Summary
To calculate the unit vector for walking downslope on a mountain contour with a gradient of h(x,y)=2xy, x^2 at point (1,3) and an angle of 45 degrees, the derivative in the direction of the unit vector (a, b) is given by the dot product 2xya + x^2b. The condition for walking downslope at a 45-degree angle requires that this dot product equals 1, while the unit vector must satisfy the equation a^2 + b^2 = 1. The discussion highlights the confusion between precalculus and calculus terminology, particularly regarding derivatives and integrals. Participants emphasize the need to solve for a and b in terms of x and y to find the correct direction. Overall, the thread focuses on applying calculus concepts to determine the appropriate unit vector for the given scenario.
hexa
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I'll be greatful for any hint.

Imagine you walk over the contourlines of the map of a mountain (really! that's the question) with a gradient of h(x,y)=2xy, x^2). You are at point (1,3) and you want to walk downslope at an angle of 45 degrees. calculate the unit vector in order to find out in which direction to walk.

Hexa
 
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What's this doing in precalculus? This is a partial derivative problem. If the gradient is (2xy, x2), then the derivative in the direction of unit vector (a, b) is just the dot product, 2xya+ x2b. If you are walking downslope at an angle of 45 degrees, then the slope must be tan(45)= 1. You want 2xya+ x2b= 1 and, of course, a2+ b2= 1. Solve for a and b in terms of x and y.
 
Thanks a lot for your help. I'll work on with this.

Calculus: not a term used in this country, so I'm not quiet sure where the border is between precalculus and calculus.
 
Then you might say "analysis" or "applied analysis". Essentially, derivatives and integrals are calculus. The basics of limits might be in calculus or pre-calculus.
 
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