- #1

radenbimayoga

- 1

- 0

I don't find anything about applicable method to solve this case (pinhole leakage), i just find calculation of pipeline rupture

Thank You

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In summary, the conversation discusses the calculation of volume for an oil spill from a pinhole in a pipeline. The participants mention the need for the diameter of the pinhole and the pressure of the fluid to accurately calculate the volume. One participant suggests using a known volume and time to determine the gallons per minute leakage.

- #1

radenbimayoga

- 1

- 0

I don't find anything about applicable method to solve this case (pinhole leakage), i just find calculation of pipeline rupture

Thank You

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- #2

jedishrfu

Mentor

- 14,938

- 9,410

I think you need those two items at the very least to properly compute it.

If I had a pinhole leak in a garden hose, I'd catch the water in a bucket of known volume and time how long it took to fill it up and from there I could get the gallons per minute leakage.

To calculate the volume of oil released from a pinhole, you will need to know the diameter of the pinhole, the pressure of the oil, and the duration of the release. These factors can be used in a formula to calculate the volume of oil released.

The formula for calculating the volume of oil released from a pinhole is: Volume = (pi * (diameter/2)^2) * pressure * time, where pi is a constant value of 3.14, the diameter is in meters, pressure is in pascals, and time is in seconds.

Yes, the volume of oil released from a pinhole can be accurately calculated as long as the necessary measurements (diameter, pressure, and time) are known and the formula is applied correctly. However, there may be some variations due to factors such as oil viscosity and environmental conditions.

The diameter should be measured in meters, pressure in pascals, and time in seconds. It is important to use the correct units in the formula to ensure accurate results.

If the pinhole is small and the oil is released under constant pressure, a simplified formula can be used: Volume = (pi * diameter^2) * time. However, this method may not be as accurate as the full formula and should only be used in specific circumstances.

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